Standard C++ doesn't provide a way to do this. You could use the system command to initialize the ls command as follows:
#include<iostream>
int main () {
char command[50] = "ls -l";
system(command);
return 0;
}This will give the output:
-rwxrwxrwx 1 root root 9728 Feb 25 20:51 a.out -rwxrwxrwx 1 root root 131 Feb 25 20:44 hello.cpp -rwxrwxrwx 1 root root 243 Sep 7 13:09 hello.py -rwxrwxrwx 1 root root 33198 Jan 7 11:42 hello.o drwxrwxrwx 0 root root 512 Oct 1 21:40 hydeout -rwxrwxrwx 1 root root 42 Oct 21 11:29 my_file.txt -rwxrwxrwx 1 root root 527 Oct 21 11:29 watch.py
If you're on windows, you can use dir instead of ls to display the list.
You can use the direct package(https://github.com/tronkko/dirent) to use a much more flexible API. You can use it as follows to get a list of files:
#include <iostream>
#include <dirent.h>
#include <sys/types.h>
using namespace std;
void list_dir(const char *path) {
struct dirent *entry;
DIR *dir = opendir(path);
if (dir == NULL) {
return;
}
while ((entry = readdir(dir)) != NULL) {
cout << entry->d_name << endl;
}
closedir(dir);
}
int main() {
list_dir("/home/username/Documents");
}This will give the output:
a.out hello.cpp hello.py hello.o hydeout my_file.txt watch.py
