How to catch IndexError Exception in Python?

When I am running the following code, I am getting error

my_list = [3,7, 9, 4, 6]
print my_list[6]

How do I catch this exception and know its type?

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1 Answer

codefoxx

Answered on 6th Dec, 2017

An IndexError is raised when a sequence reference is out of range.

The given code is rewritten as follows to catch the exception and find its type

import sys
try:
my_list = [3,7, 9, 4, 6]
print my_list[6]
except IndexError as e:
print e
print sys.exc_type

OUTPUT

C:/Users/TutorialsPoint1~.py
list index out of range
<type 'exceptions.IndexError'>

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