How to catch NameError Exception in Python?

If I run the following code, I get an error

def foo():
    print magnolia
foo ()

How to catch this exception and find its type?

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1 Answer

codefoxx

Answered on 6th Dec, 2017

NameErrors are raised when your code refers to a name that does not exist in the current scope. For example, an unqualified variable name.

The given code is rewritten as follows to catch the exception and find its type.

import sys
try:
def foo():
print magnolia
foo()
except NameError as e:
print e
print sys.exc_type

OUTPUT

C:/Users/TutorialsPoint1/~.py
global name 'magnolia' is not defined
<type 'exceptions.NameError'>

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