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How to catch OverflowError Exception in Python?

If I run the following code, I get an error

i=1
f = 3.0**i
for i in range(100):
    print i, f
    f = f ** 2

How do I catch this exception and know its type?


1 Answer
codefoxx

When an arithmetic operation exceeds the limits of the variable type, an OverflowError is raised. Long integers allocate more space as values grow, so they end up raising MemoryError. Floating point exception handling is not standardized, however. Regular integers are converted to long values as needed.

Given code is rewritten to catch exception as follows

i=1
try:
f = 3.0**i
for i in range(100):
print i, f
f = f ** 2
except OverflowError as err:
print 'Overflowed after ', f, err

We get following OverflowError as output as follows

C:/Users/TutorialsPoint1/~scratch_1.py
Floating point values:
0 3.0
1 9.0
2 81.0
3 6561.0
4 43046721.0
5 1.85302018885e+15
6 3.43368382029e+30
7 1.17901845777e+61
8 1.39008452377e+122
9 1.93233498323e+244
Overflowed after 1.93233498323e+244 (34, 'Result too large')

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