How to handle a python exception within a loop?

I have a code using 'for loop' that throws an exception.

a=[]
foo = 'redbullz'
for i in foo:
a.append(i)
print a[8]

How do I catch this exception in the loop in above code?

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1 Answer

Rajendra Dharmkar

Answered on 7th Dec, 2017

We can the exception in the code by rewriting it as follows

a=[]
foo = 'redbullz'
try:
for i in foo:
a.append(i)
print a[8]
except Exception as e:
print e

We get following output

list index out of range
Process finished with exit code 0

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