How to raise an exception in one except block and catch it in a later except block in Python?

Python Server Side Programming Programming

I would like to know if it is possible in python to raise an exception in one except block and catch it in a later except block. I have tried to implement this in code below, however it is not working.

 try:
   something
except SpecificError, ex:
   if str(ex) = "some error I am expecting"
      print "close softly"
   else:
      raise
except Exception, ex:
   print "did not close softly"
   raise

I want the raise in the else clause to trigger the final except statement.

How to catch the exception in a later except block?

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1 Answer

Manogna

Answered on 6th Dec, 2017

Only a single except clause in a try block is invoked. If you want the exception to be caught higher up then you will need to use nested try blocks.

Let us write 2 try...except blocks like this:

try:
try:
1/0
except ArithmeticError as e:
if str(e) == "Zero division":
print ("thumbs up")
else:
raise
except Exception as err:
print ("thumbs down")
raise err

we get the following output

thumbs down
Traceback (most recent call last):
File "C:/Users/TutorialsPoint1/~.py", line 11, in <module>
raise err
File "C:/Users/TutorialsPoint1/~.py", line 3, in <module>
1/0
ZeroDivisionError: division by zero

As per python tutorial there is one and only one caught or catched exception per one try statement.

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How to raise an exception in one except block and catch it in a later except block in Python?

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