Implementation of FizzBuzz involves printing numbers from 1 to 100. If the numbers are multiples of 3 then Fizz is printed. If they are multiples of 5, then Buzz is printed and if they are multiples of both 3 and 5 then FizzBuzz is printed.
A program that demonstrates the implementation of FizzBuzz is given as follows.
using System;
namespace FizzBuzzDemo {
public class example {
static void Main(string[] args) {
for (int i = 1; i <= 100; i++) {
if (i % 3 == 0 && i % 5 == 0) {
Console.WriteLine("FizzBuzz");
} else if (i % 3 == 0) {
Console.WriteLine("Fizz");
} else if (i % 5 == 0) {
Console.WriteLine("Buzz");
} else {
Console.WriteLine(i);
}
}
}
}
}
The output of the above program is as follows.
1 2 Fizz 4 Buzz Fizz 7 8 Fizz Buzz 11 Fizz 13 14 FizzBuzz 16 17 Fizz 19 Buzz Fizz 22 23 Fizz Buzz 26 Fizz 28 29 FizzBuzz 31 32 Fizz 34 Buzz Fizz 37 38 Fizz Buzz 41 Fizz 43 44 FizzBuzz 46 47 Fizz 49 Buzz Fizz 52 53 Fizz Buzz 56 Fizz 58 59 FizzBuzz 61 62 Fizz 64 Buzz Fizz 67 68 Fizz Buzz 71 Fizz 73 74 FizzBuzz 76 77 Fizz 79 Buzz Fizz 82 83 Fizz Buzz 86 Fizz 88 89 FizzBuzz 91 92 Fizz 94 Buzz Fizz 97 98 Fizz Buzz
Now, let us understand the above program.
A for loop runs from 1 to 100 and creates the numbers required. Then a series of if statements are used to find if the number i is divisible by 3, by 5 or by both. If the number is only divisible by 3, Fizz is printed. If the number is only divisible by 5, Buzz is printed and if the number is divisible by both, then FizzBuzz is printed. Otherwise, the number is printed. The code snippet for this is as follows −
for (int i = 1; i <= 100; i++) {
if (i % 3 == 0 && i % 5 == 0) {
Console.WriteLine("FizzBuzz");
}else if (i % 3 == 0) {
Console.WriteLine("Fizz");
} else if (i % 5 == 0) {
Console.WriteLine("Buzz");
} else {
Console.WriteLine(i);
}
}
