Please note, this is a STATIC archive of website www.tutorialspoint.com from 11 May 2019, cach3.com does not collect or store any user information, there is no "phishing" involved.
Tutorialspoint

1 Answer
karthikeya Boyini

Here we use .zip() for iterative over multiple lists simultaneously.zip() takes n number of iterables and returns list of tuples. i-th element of the tuple is created using the ith element from each of the iterables.

Example

L1=[1,2,3,4]
L2=[‘aa’,’bb’,’cc’,’dd’]
L=zip(L1,L2)
Output
[(1,’aa’),(2,’bb’),(3,’cc’),(4,’dd’)]

Algorithm

Step 1: first create 3 user input list.
Step 2 : use .zip() function.
Step 3: print tuples.

Example code

# To iterate over 3 lists using zip function
importitertools
A=list()
B=list()
C=list()
n = int(input("How many you data want to store??"))
print("Enter Roll no.")
for i in range(int(n)):
   k=int(input(""))
   A.append(k)
print("Enter Name ::")
for j in range(int(n)):
   k1=input("")
   B.append(k1)
print("Enter Age ::")
for j in range(int(n)):
   k1=int(input(""))
   C.append(k1)
print ("\niterating using zip")
for (a, b, c) in zip(A, B, C):
   print (a, b, c)

Output

How many you data want to store??4
Enter Roll no.
56
89
67
34
Enter Name ::
yui
jkl
vm
dfg
Enter Age ::
7
9
6
5
iterating using zip
56 yui 7
89 jkl 9
67 vm 6
34 dfg 5

Advertisements

We use cookies to provide and improve our services. By using our site, you consent to our Cookies Policy.