Aptitude - Averages Online Quiz

Answer : D

Explanation

5 number have the total sum = (18*5)= 90
4 number have the total sum = (16*4)= 64
So, the exclude number is = (90-64)= 26.

Q 2 - 37 °C is mean temperature of 3 days Monday, Tuesday, Wednesday while 34°C is average of Tuesday, Wednesday and Thursday . What should be the temperature on Thursday if the temperature was 4/5 of that of Monday?

Answer : B

Explanation

M+ T+W =(37*3) = 111...(i)
T+W+Th= (34*3) = 102 ...(ii)
Th =4/5m ⇒ M = 5/4*th ...(iii)
(ii)-(i)  gives , M-Th = 9 ⇒ 5 Th /4 � Th =9
If we assume that x° is the temperature on Thursday. Then,
5x/4 �x =9 ⇒ 5x-4x = 36 ⇒ x = 36°
Hence, its proves that the Thursday temperature was 36°.

Q 3 - 15 year is the average age of 40 students. The average increase 0.2 year if we calculate the average age of 50 students . Find the average age of 10 students?

Answer : B

Explanation

40 student have total age = 15*40 =600 years
50 student have total age = 15.02*50 = 760 year
10 student have total age = 760- 600 = 160 year
So, the average age of 10 student is = 160/10 = 16 year.

Q 4 - Find out the average speed of the journey if with the speed of 6km/hr covers half distance and remaining half covers by the speed of 3 km/hr.

Answer : B

Explanation

Average speed = 2xy / (x+y)km/hr = 2*6*3/ (6+3)km/hr = 4km/hr

Q 5 - With the average of 12.4 takes 5 wickets by use of 26 run. A player has 0.4 downfalls in his average. What should be the number of wicket taken by him before the last match played?

Answer : A

Explanation

x is the number of wickets taken a player  before the last match played.
Then, (12.4x+26)/(x+5) =12 ⇒ 12.4x+26 =12x+60 ⇒ 0.4x =34
⇒ 0.4x =34 ⇒ x= 34/0.4 ⇒ x =340/4 = 85.
Wickets required = 85.

Q 6 - Drinks were done by 6 persons. Out of them 5 person paid 32 Rs. each, Rs. 80 more paid by the 6th person in the comparison of average expenditure of all. Find out the total amount paid by 6 persons?

Answer : A

Explanation

if x is the average  expenditure  of 6 person.
(32*5)+(x+80)= 6x = 5x = (160+80) = 5x= 240 ⇒ x = 48
Total expenditure  = 48*6  =288 Rs.

Q 7 - A grocer has a sale of Rs. 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must be have in the sixth month so that he gets an average sale of Rs. 6500?

Answer - D

Explanation

Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009. 
Therefore Required sale = Rs. [(6500 6) - 34009] = Rs. (39000 - 34009) = Rs. 4491

Q 8 - Of the four numbers, the first is twice the second, the second is one-third of the third and the third is 5 times the fourth. The average of the numbers is 24.75. The largest of these numbers is?

Answer - A

Explanation

Let the fourth number be z. 
then, third number = 5z, second number = ^5z⁄₃ and first number = ^10z⁄₃ 
z + 5z + ^5z⁄₃ + ^10z⁄₃ = (24.75 x 4) or 11z = 99 or z = 9 
So, the numbers are 9, 45, 15, and 30. 
Therefore Largest number = 45.

Q 9 - The captain of a cricket team of 11 members is 26 years old and the wicket keeper is 3 years older. If the ages of these two are excluded the average age of the remaining players is one year less than the average age of the whole team. What is the average age of the team?

Answer - B

Explanation

Let the average age of the whole team be z years. 
Therefore 11z - (26 + 29) = 9 (z - 1) = 11z - 9z = 46 
= 2z = 46
= z = 23 

So, average age of team is 23 years.

Q 10 - The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is?

Answer - A

Explanation

Sum of the present ages of husband, wife and child = (27 x 3 + 3 x 3) years = 90 years. 
Sum of the present ages of wife and child = (20 x 2 + 5 x 2) years = 50 years 
Therefore Husbands present age = (90 - 50) years = 40 years

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