Aptitude - Squares & Cubes Online Quiz



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Following quiz provides Multiple Choice Questions (MCQs) related to Squares & Cubes. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - √1296 =(?)2

A - 6

B - 1296

C - 625

D - 36

Answer : A

Explanation

Let √1296 = x2, Then ,x2=36
 ∴  x =√36 = 6

Q 2 - √4375/√7 = ?

A - 24.75

B - 27.25

C - 25

D - 35

Answer : C

Explanation

√4375/√7 = √4375/√7 = √625 = 25

Q 3 - given that √3= 1.732, the value of 3 +√6 /(5√3-2√12 -√32+√50)is:

A - 4.899

B - 2.551

C - 1.414

D - 1.732

Answer : D

Explanation

Given exp = 3+√6/(5√3-2√4*3-√16*2+ √25*2)
= 3+√6/(5√3-4√3-4√2+5√2)
= (3+√6)/( √3+√2)*( √3-√2)/( √3-√2)
= 3√3-3√2+√18-√12/(3-2)
=(3√3-3√2+√9*2 -√4*3 )= (3√3-3√2+3√2-2√3) =√3= 1.732

Q 4 - 36.1/102.4 =?

A - 29/32

B - 19/72

C - 19/32

D - 29/62

Answer : C

Explanation

√36.1/102.4  = √361/1024 = √361/ √1024 =19/32

Q 5 - 0.0196/? = 0.2

A - 0.49

B - 0.7

C - 4.9

D - none of these

Answer : A

Explanation

let √0.196/x = 0.2. then, 0.0196/x = (0.2)2=0.04
∴ 0.04*x = 0.0196 ⇒ x= 0.0196/0.0400= 196/400 = 49/100= 0.49

Q 6 - √(0.49/0.25) + √(0.81/0.36) = ?

A - 9/10

B - 29/10

C - 79/10

D - 99/10

Answer : B

Explanation

√0.49/0.25 = √ 49/25 =7/5, √ 0.81/0.36 = √81/36 = 9/6 =3/2
Given expression = 7/5+3/2= (14+15)/10  = 29/10

Q 7 - The value of √3+1/√3-1+ √3-1/√3+1 is:

A - 1

B - 2

C - 2√3

D - 4

Answer : D

Explanation

(√3+1/√3-1+ √3-1/√3+1)= (√3+1)2+( √3-1)2/(3-1) = 2(3+1)/2= 4

Q 8 - {(√2-1)2+( √2-1)2/(2-1)]/ [(√3-1)2+ (√3+1)2/(3-1)] = ?

A - 2/3

B - 3/2

C - 4

D - 6

Answer : B

Explanation

given Expression =
{(√2-1)2+( √2-1)2/(2-1)]/ [(√3-1)2+ (√3+1)2/(3-1)] =2(2+1)/1*2/2(3+1)= 3/2

Q 9 - The value of 1/(√2+1)+1/(√3+√2)+1/(√4+√3)...+1/(√121+√120) is

A - √120

B - 12√2

C - 8

D - 10

Answer : D

Explanation

given exp. =1/(√2+1)+1/(√3+√2)+1/(√4+√3)...+1/(√121+√120)
=1/(√2-1)* √2-1)/( √2-1)+1/(√3+√2)* √3-√2/√3-√2+1/(√4+√3)*( √4-√3)/( √4-√3)+?..+1/√121+√120*(√121-√120/√121-√120
= (√2-1)+( √3-√2)+( √4-√3)?..+( √121-√120) =(√121-1)
= (11-1) = 10.  ≤

Q 10 - 1250 oranges were distributed among a group of girls of a class. Each girls got twice as many oranges as the number of girls in that group . The number of the girls was :

A - 25

B - 45

C - 50

D - 100

Answer : A

Explanation

let there be x girls in the group. Each girl got 2x oranges.
∴ 2x*x = 1250  ⇒ 2x2 =1250  ⇒ x2 =625 ⇒ x= √625  =25
Number of girls in the group= 25


aptitude_squares_cubes.htm

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