Volume Calculation - Online Quiz



Advertisements


Following quiz provides Multiple Choice Questions (MCQs) related to Volume Calculation. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.

Questions and Answers

Q 1 - An iron shaft is 9 m long, 40 cm wide and 20 cm high. In the event that 1 cubic meter of iron measures 50 kg. What is the heaviness of the bar?

A - 56 kg

B - 48 kg

C - 36 kg

D - 27 kg

Answer : C

Explanation

Volume of beam = (9*40/100*20/100)m3=  18/25m3
Weight of the bean = (18/25*50) kg = 36 kg

Q 2 - A rectangular water tank is open at the top. Its ability is 24m3. Its length and broadness are 4m and 3m separately. Overlooking the thickness of the material utilized for building the tank, the aggregate expense of painting the internal and external surfaces of the tank at Rs 10 for every m2, is:

A - Rs 400

B - Rs. 500

C - Rs. 600

D - Rs. 800

Answer : D

Explanation

Let the depth of the tank be x meters. Then, 4*3*x = 24 ⇒x =2m
Area of the surface to be painted = 2* [{2*(L+b)*h} + (L*b)}]
= 2*[2*(4+3)*2+ (4*3)] m2= 80m2
Cost of painting = (80*10) = 800 Rs.

Q 3 - The measurements of a cuboid are a, b,c units, its volume is V cubic units and its entire surface zone is S sq. units. At that point, 1/V=?

A - S/2(a+b+c)

B - 2/S(1/a + 1/b+ 1/c)

C - 2S(a+b+c)

D - 2S/(a+b+c)

Answer : B

Explanation

1/V =(1/S*S/V) = 2(ab+bc+ca)/s*abc=   2/S(1/a+1/b+1/c)

Q 4 - A store is 15m long and 6m expansive. The amount of water taken out to bring down the level by 1 m is:

A - 90 ltr.

B - 70 kiloliter

C - 80 kiloliter

D - 90 kiloliter

Answer : D

Explanation

Let the initial depth be x meters. Then,
Quantity Of water taken out = [(15*6*x)- {15*6*(x-1)}]m3
=[90x-(90x-90)]m3= 90m3= 90 kiloliters.

Q 5 - The region of three contiguous appearances of a cuboid are in the proportion 2:3:4 and its volume is 9000 cm3. The littlest side has a length of:

A - 10 cm

B - 15 cm

C - 20 cm

D - 30 cm

Answer : B

Explanation

Let the area of the three adjacent faces be 2x, 3x and 4x then,
Lb= 2x, bh= 3x and Lh= 4x
∴ (Lb*bh*Lh) = 24x3 ⇒ (Lbh) 2 =(9000) 2= 81000000
⇒x3= 81000000/24= 27000000/8 ⇒x = 300/2= 150
∴ Lb= 300, bh =450 and Lh= 600 and Lbh= 9000
∴ h = 9000/300= 30cm, L= 9000/450 = 20cm, b= 9000/600= 15cm
Smallest side = 15 cm

Q 6 - The size of a wooden square is (15 cm *12 cm* 20 cm) . What number of such pieces will be required to build a strong wooden solid shape of least size?

A - 45

B - 48

C - 60

D - 75

Answer : C

Explanation

Side of smallest cube = LCM (15cm, 12cm, 20cm) =60cm
Volume of such a cube =(60*60*60) cm3
Volume of 1 given block = (15*12*20) cm3
Required no. of blocks= (60*60*60/15*12*20) =60

Q 7 - If every side of a 3D square of volume v is multiplied, its volume gets to be ℏv where ℏ is equivalent to:

A - 2

B - 4

C - 8

D - 16

Answer : C

Explanation

Let each side be a, then, V= a3
New volume = (2a) 3= 8a3= 8V
∴ℏV= 8V⇒ℏ= 8

Q 8 - The bended surface of a tube shaped column is 264 m2 and its volume is 924 m3. The proportion of its width to its stature is:

A - 7:3

B - 3:7

C - 7:6

D - 6:7

Answer : A

Explanation

2πrh =264 and πr2h =924
∴πr2h/2πrh=   924/264= 7/2 ⇒r =7 ⇒d= 2r =14m
2*22/7*7*h =264 ⇒h = 264/44= 6
∴ d/h= 14/6=    7/3 = 7:3

Q 9 - Two barrel have break even with volumes and their statures are in the proportion 1:3. The proportion of their radii is

A - 4:√3

B - 3:2√3

C - 2:√3

D - 3:√3

Answer : D

Explanation

Let their radii be R and r and the heights be h and 3h.
Then πR2h = πr2*3h⇒ R2/r2 =3 ⇒(R/r) 2 = (√3)2
⇒R/r= √3/1 = 3/√3
∴ R: r = 3:√3

Q 10 - In the event that the sweep of a circle is multiplied, its surface region will increment by:

A - Half

B - 200 %

C - 300%

D - 400%

Answer : C

Explanation

Let, original radius=r. Then surface area= 4πr2
New radius= 2r. New surface area = 4π (2r) 2= 16πr2
Increase % in surface areas = (12πr2/4 πr2*100) %= 300%


aptitude_volume_calculation.htm

Advertisements