Aptitude - Calendar Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Calendar. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Q 1 - On What dates of March 2005 did Friday fall?
Answer : B
Explanation
To begin with we discover the day on 1.3.2005. 1.3.2005= (2004 year+ period from 1.1.2005 to 1.3.2005 Odd days in 1600 years = 0 Odd days in 400 years = 0 4 years = (1 jump year+ 3 normal years) = (1*2+3*1) odd days = 5 odd days. Jan + Feb + March 31 + 28 + 1 = 60 days = (8 weeks +4 days)=4 odd days. ∴ Total number of odd days = (0+0+5+4) =9=2 odd days. ∴ 1.3.2005 was Tuesday. So, Friday lies on 4.3.2005. Thus, Friday lies on 4th, 11th, 18th and 25th of March, 2005.
Q 2 - What was the week's day on sixteenth July, 1776?
Answer : B
Explanation
16 July, 1776 = (1775 years + period from 1.1.1776 to 16.7.1776. Checking of odd days. No. of odd days in 1600 years =0 No. of odd days in 100 years = 5 75 years= 18 jump years+57 conventional years = (18*2+57*1) odd days = 93 odd days = (13 weeks +2 days) = 2 odd days. ∴ 1775 years have= (0+5+2) odd days= 7 days= 0 days Jan + Feb. + March + April + May + June + July 31 +29 + 31 + 30 + 31 + 30 +16 = 198 days 198 days = (28 weeks+2 days) = 2 odd days =Total no. of odd days = (0+2) = 2 Thus, the required day is Tuesday.
Q 3 - On eighth Dec, 2007 Saturday falls. What was the day of the week would it say it was on eighth dec, 2006?
Answer : D
Explanation
The year 2006 is a common year. Along these lines, it has 1 odd day. In this way, the day on eighth Dec, 2007 will be 1 day past the day. On eighth Dec, 2006. Yet, eighth Dec,2007 is Saturday. ∴ eighth Dec, 2007 is Friday.
Q 4 - The calendar for the year 2007 will be the same for the year:
Answer : D
Explanation
Count the number of odd days from the year 2007 onwards, to get the sum equal to 0 odd days.
years | 2007 | 2008 | 2009 | 2010 | 2011 | 2012 | 2013 | 2014 | 2015 | 2016 | 2017 |
---|---|---|---|---|---|---|---|---|---|---|---|
Odd Days | 1 | 2 | 1 | 1 | 1 | 2 | 1 | 1 | 1 | 2 | 1 |
Q 5 - on what dates of April, 2001 did Wednesday fall?
Answer : D
Explanation
We might discover the day on first April, 2001. First April , 2001=(2000 year + Period structure 1.1.2001 to 1.4.2001) Odd days in 1600 years =0. Odd days in 400 year =0. Jan Feb March April 31 + 28 + 31 + 1 = 91 days =0 odd day. Aggregate number of odd days= (0+0+0) =0. On first April, 2001 it was Sunday. In April, 2001 Wednesday falls on 4th, 11th, 18th and 25th.
Answer : D
Explanation
28.May,2006 =(2005 years +Period structure 1.1.2006 to 28.5.2006) Odd days in 1600 years=0. Odd days in 400 years = 0. 5 years = (4 common years+ 1 jump years)=(4*1+1*2)odd days = 6 odd days. Jan + Feb. + March + April + May 31 + 28 + 31 + 30 + 28 =148 days. 148 days = (21 weeks+1 day) = 1 odd day Aggregate no. of odd days = (0+0+6+1) = 7= 0 odd day. Given day is Sunday.
Answer : C
Explanation
100 years contain 5 odd days. ∴ Last day of first century is Friday. 200 years contain (5*2) = 3 odd days. ∴ Last day of second century is Wednesday. 300 year contain (5*3) =15=1 odd day. ∴ Last day of third century is Monday. 400 year contain 0 odd days. ∴ Last day of fourth century is Sunday. The cycle is repeated. ∴ Last day of a century can't be Tuesday or Thursday or Saturday.
Answer : A
Explanation
The century divisible by 400 is a leap year. ∴ The year 700 is not a jump year.
Q 9 - On eighth Feb, 2005 it was Tuesday. What was the week's day on eighth Feb, 2004?
Answer : C
Explanation
The year 2004 is a jump year. It has 2 odd days. ∴ The day on eighth Feb,2004 is 2 days before the day. On eighth Feb, 2005. Henceforth This day is Sunday.