Integral Calculus Problem Example 2
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Description:
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.intsuma > span {
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.intsuma .lim-up {
margin-bottom: 0ex;
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.intsuma .lim {
margin-top: -0.5ex;
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.intsuma .sum {
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.intsuma .sum-frac {
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Problem
Find the area enclosed by the curve y = sin x, with the X-axis, between x = 0 and x = π.
Solution
For any function, y = f(x), Area under the curve between x = a and x = b is −
b∫a f(x) . dx
In our problem,
- f(x) = sin x
- a = 0
- b = π
Hence,
Area = π∫0 sin x . dx = -cos x]π0
Area = -(cos π - cos 0) = 2
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