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Integral Calculus Problem Example 3


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Published on:  on 7th Apr, 2018

Description:

Problem

Find the area bounded by the curve y = e-x, the X − axis and the Y − axis.

Solution

Plot of y = e-x, looks like following −

Area Enclosed

  • The curve in magenta represents, y = e-x.
  • The area shaded in green represents the area bounded by the curve, X-axis and Y-axis.

Now,

For any function, y = f(x), Area under the curve between x = a and x = b is −

ba f(x) . dx

In our problem,

  • f(x) = e-x
  • a = 0
  • b = ∞,

Hence,

Area = 0 e-x . dx

Substitution, t = -x, Hence, dt = -dx

Area = -∞0 -et . dt = -et]-∞0 = -[e-∞ - e0] = -[0 - 1] = 1

Note

If the graph of y = e-x, is unknown to a student, he/she may still be able to deduce the correct limits of integration. Following steps should be followed for the same −

  • The problem asks us to find the area bounded by the curve, y = e-x, the X − axis and the Y − axis.

  • We know the limits of integration are the two values of ‘x’.

  • Therefore, the Y − axis intersects the X − axis only at x = 0. Hence, one of the limits is certainly x = 0.

  • The curve, y = e-x, will intersect X − axis at y = 0 or e-x = 0. Therefore, in this case, x → ∞.

Hence, the limits will be from x = 0 to x → ∞.


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