Vectors Problem Example 5
Description:
.fraction {
display: inline-block;
vertical-align: middle;
margin: 0 0.2em 0.4ex;
text-align: center;
}
.fraction > span {
display: block;
padding-top: 0.15em;
}
.fraction span.fdn {border-top: thin solid black;}
.fraction span.bar {display: none;}
.sy {
position: relative;
text-align: left;
}
.oncapitals, .onsmalls {
position: absolute;
top: -1.3em;
left: 2px;
width: 100%;
font-size: 70%;
text-align: center;
}
.onsmalls {
top: -1.3em;
}
Problem
Show that the area of the triangle contained between the vectors a→ and b→ is one half of the magnitude of a→ × b→.
Solution
Visualizing the triangle created by the vectors a→ and b→,
Shaded region is the area enclosed by the triangle.
In ΔABC,
AC = |b→|
AB = |a→|
Construct the altitude, CD, in the triangle.
sinθ = CDAC
CD = AC sinθ = |b→| sin θ
Area = 12 × base × altitude
Area = 12 × AB × CD
Area = 12 × |a→| × |b→| sinθ
Also,
|a→ × b→| = |a→| × |b→| × sinθ
Hence,
Area = 12 |a→ × b→|