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Ampere's Law Magnetic Field due to Current In Cylinder


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Published on:  on 10th Apr, 2018

Description:

Consider a long current carrying cylindrical conductor and a point P at a distance ‘r’ from the axis of the cylinder.

Cylinder

To find the strength of magnetic field at point P we will follow the following steps:

  • P is outside the conductor at distance ‘r’

    Draw the Amperean loop in shape of co-axial circle or radius r. Magnetic field is also circular in direction and same at every point.

    θ = 0 (Bdl)

    B.dl = ∮ B.dlcosθ =  B ∮ dl

    = B2πr

  • Calculating the current through the loop-

    Current through the loop = i

  • Applying Ampere’s law

    B.dl = μ0i

    Putting values B2πr = μ0i

    Hence, strength of magnetic field due to cylindrical conductor is-

    Bout =
    μ0i/2πr

    Bsurface =
    μ0i/2πR

    Bin =
    μ0i/2πR2
    r

    B at centre is zero.


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