Please note, this is a STATIC archive of website www.tutorialspoint.com from 11 May 2019, cach3.com does not collect or store any user information, there is no "phishing" involved.

Magnetic Field Due to Current Carrying Circular Coil Special Cases


Advertisements

Published on:  on 10th Apr, 2018

Description:

Magnetic field due to current carrying circular coil on its axis is –

B =
μ0/
2NIA/(a2 + x2)3/2

Current Coil

If 𝒙 is far away from the center of coil:

At a very large distance when x >> a,

B =
μ0/
2NIA/x3

Considering N=1,

B =
μ0/
2Iπa2/x3

∴ B =  
μ0I/2
a2/x3

Hence,

B α 1/x3

This is similar to Electric Dipole.

If 𝒙 is zero i.e. point P is at centre:

∴ B =
μ0/
2NIA/a3

Considering N=1

B =
μ0/
2Iπa2/a3

∴ B =
μ0I/2a

By observing magnetic field along the complete axis we conclude that any charge moving in the circle behaves as a magnet.

Magnet

Coil behaves like a bar magnet.


Advertisements