Please note, this is a STATIC archive of website www.tutorialspoint.com from 11 May 2019, cach3.com does not collect or store any user information, there is no "phishing" involved.

Motion of Charged Particle In A Magnetic Field


Advertisements

Published on:  on 10th Apr, 2018

Description:

If a charge ‘q’ is moving with velocity v enters in uniform magnetic field B, the magnetic force acting on the particle is given by,

FB = qV ×B

The direction of magnetic force is same as v×B if charge is positive and opposite if charge is negative.

Cases of Projection

Case I : If velocity of charge particle v is parallel to B then -

Projection

F = q V B Sin 0o ⇒ F = 0

Case II: If a charge enters a magnetic field at right angle to it, it moves in a circular path due to magnetic force which acts as a centripetal force.

Centripetal Force

Centripetal force is given by –

FB =
mV2/r

Where,

m = Mass of the particle,

V = Linear velocity,

r = Radius of circular path.

As we know –

FB = qVB

Put the value of FB

∴ qVB =
mV2/r
.......(1)

We can derive multiple relations from the above equation.

Velocity of charge

V =
qBr/m

Observation: As magnetic field increases the velocity of charge increases.

Radius of circular path

r =
mV/qB

Observation: To maintain the radius of circular path, as the magnetic field increases the velocity should also increase.

     

Angular velocity

V =
qBr/m
⇒ rω =
qBr/m

∴ ω =
qB/m
     

q/m is known as specific charge.

     

Observation: Angular velocity depends upon the specific charge and magnetic field.

Time period of rotation

ω =
/T

∴ T =
2πm/qB

Observation: As the magnetic field increases, the angular velocity increases and time period of rotation decreases.

Frequency

v =
1/T

∴ v =
qB/2πm

Observation: As the time period of rotation increases, the frequency of rotation decreases.

Kinetic energy of the rotating charge

K.E =
1/2
mv2

∴ K.E =
q2B2r2/2m
       


Advertisements