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Elimination Problem 9


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Published on:  on 10th Apr, 2018

Description:

Problem

What would be the major product (alkene) obtained when the following alkyl halides react with NaOEt?

1. 1 − Bromo − 1 − methylcyclohexane

2. 2 − Chloro − 2 − methylbutane

3. 2,2,3 − Trimethyl − 3 − bromopentane

Solution

  • Dehydrohalogenation is the reaction in which elimination of X and H atoms take place from α and β −carbons.

  • When more than 1 β − hydrogen atoms are present, multiple alkenes can  be formed.

  • The more stable alkene will be the major product.

1. 1 − Bromo − 1 − methylcyclohexane reacts with EtO: two different alkenes are formed. The one with the maximum alkyl groups attached to the double bond is the most stable alkene and hence the major product.

Cyclohexane

2. When  2 − Chloro − 2 − methylbutane reacts with EtO, two alkenes are formed. Major product will be the more stable alkene or the more substituted double bond.

Double Bond

3. When 2,2,3 − Trimethyl − 3 − bromopentane reacts with EtO

Trimethyl


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