Problem on Preparation from Alkenes

Description:

Problem − Give the final products obtained in each of these reactions.

Solution −

A. Addition of HBr across double bond results in markovnikov’s product with bromine attaching to carbon with fewer number of hydrogen atoms.

B. CH₃ - CH₂ - CH = CH₂ + Cl₂ → CH₃ - CH₂ - CH(Cl) - CH₂Cl

Addition of halogen across double bond resulting in the formation of vicinal dihalides

C. Addition of HBr/H₂O₂, results in the formation of antimarkovnikov’s product with bromine attaching to carbon atom with more number of hydrogen atoms.