Hybridization - Problem 1
Advertisements
Description:
Problem − Give the hybridization states of each of the carbon atom in the given molecule.
A. H2C = CH − CN
B. HC ≡ C − C ≡ CH
C. H2C = C = C = CH2
Solution −
The hybridization states can be determined by looking at the number of σ − bonds and lone pair of electrons.
sp hybridization state has 2 σ and 2π-bonds, while sp2 has 3σ and 1π bonds, sp3 has 4σ − bonds.
N in CN has 1σ bond and 1 lone pair of electrons. Nitrogen also requires 2 hybrid sp orbitals, one to accommodate the lone pair of electrons and 1 to form the σ − bonds with carbon.
Hybridization states are given in the table below −
A | H2C = CH − C ≡ N | sp2 − sp2 − sp − sp |
B | HC ≡ C − C ≡ CH | sp − sp − sp − sp |
C | H2C = C = C = CH2 | sp2 − sp − sp − sp𝟐 |
Advertisements