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Hybridization - Problem 1


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Description:

Problem − Give the hybridization states of each of the carbon atom in the given molecule.

A. H2C = CH − CN

B. HC ≡ C − C ≡ CH

C. H2C = C = C = CH2

Solution

  • The hybridization states can be determined by looking at the number of σ − bonds and lone pair of electrons.

  • sp hybridization state has 2 σ and 2π-bonds, while sp2 has 3σ and 1π bonds, sp3 has 4σ − bonds.

  • N in CN has 1σ bond and 1 lone pair of electrons. Nitrogen also requires 2 hybrid sp orbitals, one to accommodate the lone pair of electrons and 1 to form the σ − bonds with carbon.

  • Hybridization states are given in the table below −

AH2C = CH − C ≡ Nsp2 − sp2 − sp − sp
BHC ≡ C − C ≡ CH sp − sp − sp − sp
CH2C = C = C = CH2sp2 − sp − sp − sp𝟐


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