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Quantitative Analysis - Nitrogen by Dumas Method Problem


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Description:

Problem

0.30 g of an organic compound gave 30 cm3 of moist nitrogen gas at 290 K and 745 mm pressure. Calculate the percentage of nitrogen using Dumas method. (given, aqueous tension at 290 K = 12.7 mm).

Solution:

Given, mass of the substance = 0.30 g

Pressure, P1 = 745 − 12.7 mm = 732.3 mm

CondiionsPressureTemperatureVolume
StandardP1 = 732.3 mmT1 = 290 KV1 = 30 cm3
Experimentalp2 = 760 mmT2 = 273 KV2 = ??

Step I: To reduce the nitrogen to STP,

P1V1

/

T1

=

P2V2

/

T2

V2 =

P1V1 x 273

/

760 x T1

=

732.3 mm x 30 cm3 x 273 K

/

290K x 760 mm

= 27.2 cm3

Step II:  To calculate percentage of nitrogen,

22400 cm3 N2 at STP weighs = 28 g

27.2cm3 N2 in the given organic compound weighs =

28 x 27.2

/

22400

= 0.034 g

Percentage of N2 =

28 x VN2(STP) x 100

/

22400 x m

=

28 x 27.2 x 100

/

22400 x 0.30

= 11.33%


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