Quantitative Analysis - Nitrogen by Dumas Method Problem
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Problem
0.30 g of an organic compound gave 30 cm3 of moist nitrogen gas at 290 K and 745 mm pressure. Calculate the percentage of nitrogen using Dumas method. (given, aqueous tension at 290 K = 12.7 mm).
Solution:
Given, mass of the substance = 0.30 g
Pressure, P1 = 745 − 12.7 mm = 732.3 mm
Condiions | Pressure | Temperature | Volume |
---|---|---|---|
Standard | P1 = 732.3 mm | T1 = 290 K | V1 = 30 cm3 |
Experimental | p2 = 760 mm | T2 = 273 K | V2 = ?? |
Step I: To reduce the nitrogen to STP,
P1V1
T1
=
P2V2
T2
V2 =
P1V1 x 273
760 x T1
=
732.3 mm x 30 cm3 x 273 K
290K x 760 mm
= 27.2 cm3
Step II: To calculate percentage of nitrogen,
22400 cm3 N2 at STP weighs = 28 g
27.2cm3 N2 in the given organic compound weighs =
28 x 27.2
22400
= 0.034 g
Percentage of N2 =
28 x VN2(STP) x 100
22400 x m
=
28 x 27.2 x 100
22400 x 0.30
= 11.33%